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4.1.12. Navier-Stokes Momentum Equation

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4.1.12. Navier-Stokes Momentum Equation¶

  • What is the relationship between dynamic and kinematic viscosity and what are their units?

  • What is the effect of the incompressibility constraint on the Navier-Stokes equations?

  • What are the assumptions in the Navier-Stokes equations?

  • What is the relationship between the total stress tensor, normal stress and deviatoric stress?

  • What is the definition of the total stress tensor for viscous and inviscid flow?

  • How is the total stress tensor defined for the Navier-Stokes momentum equation?

  • What is the shear strain rate tensor?

  • How is the compressible Navier-Stokes momentum equation derived from the Cauchy equation using the shear strain rate tensor?

  • What are the meaning of the terms in the fully compressible Navier-Stokes equations?

  • Expand the terms in the Navier-Stokes equations assuming \(\nabla \cdot \vec{u} = 0\)

  • How is the compressibility term expanded in the Navier-Stokes equations?

  • What is the skew symmetric form of the total derivative?

4.1.12.1. What is the relationship between dynamic and kinematic viscosity and what are their units?¶

\[\nu = {\mu \over \rho}\]

Mnemonic:

Kinematic viscosity \(\ll\) Dynamic viscosity, as kinematics deals with smaller things than dynamics.

Units:

\(\nu \ (m^2/s)\)

\(\mu \ (kg/m/s)\)

\(\rho \ (kg/m^3)\)

4.1.12.2. What is the effect of the incompressibility constraint on the Navier-Stokes equations?¶

  1. \(\rho = \text{constant} \longrightarrow \nabla \cdot \vec{u} = 0\) i.e. velocity field must be divergence free

  2. \(\rho = \text{constant} \longrightarrow\) pressure and density are decoupled, i.e. pressure is no longer a state variable, it is a constant \(\longrightarrow\) require pressure-velocity coupling

4.1.12.3. What are the assumptions in the Navier-Stokes equations?¶

  1. Continuum hypothesis \(\longrightarrow Kn \ll 1\) and no mass-energy conversion

  2. Form of diffusive fluxes e.g.:
    • Newtownian \(\tau_{ij} = \mu \gamma_{ij}\)

    • Fourier’s Law \(\vec{q} = -k \nabla T\)

    • Viscosity model \(\mu = \mu(T)\) e.g. Sutherland’s Law

  3. Equation of state (but this concerns the solution)
    • Stokes assumption \({2 \over 3} \mu + \lambda = 0\)

    • Thermally perfect gas \(p=\rho RT\)

    • Calorcally perfect gas \(e=C_v T\)

4.1.12.4. What is the relationship between the total stress tensor, normal stress and deviatoric stress?¶

\[\text{Total stress tensor = Normal stress tensor + Deviatoric stress tensor}\]
\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{\sigma} = -p \overset{\underset{\mathrm{\rightrightarrows}}{}}{I} + \overset{\underset{\mathrm{\rightrightarrows}}{}}{\tau}\]

(Deviatoric stress tensor is also the shear stress tensor)

where the identity matrix is:

\[\begin{split}\overset{\underset{\mathrm{\rightrightarrows}}{}}{I} = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}\end{split}\]

4.1.12.5. What is the definition of the total stress tensor for viscous and inviscid flow?¶

Total stress tensor:

  • Pressure tensor (normal stress tensor)

  • Deviatoric stress tensor (shear stress tensor)

Inviscid:

  • Fluid only has normal force:

\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{\tau} = 0\]
  • Hence:

\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{\sigma} = -p \overset{\underset{\mathrm{\rightrightarrows}}{}}{I}\]

Viscous:

  • Fluid has shear stress:

\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{\tau} \ne 0\]
  • Hence:

\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{\sigma} = -p \overset{\underset{\mathrm{\rightrightarrows}}{}}{I} + \overset{\underset{\mathrm{\rightrightarrows}}{}}{\tau}\]

4.1.12.6. How is the total stress tensor defined for the Navier-Stokes momentum equation?¶

  • Total stress tensor:

\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{\sigma}=-p \overset{\underset{\mathrm{\rightrightarrows}}{}}{I} + \overset{\underset{\mathrm{\rightrightarrows}}{}}{\tau}\]
  • Shear stress tensor:

\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{\tau}= \mu \overset{\underset{\mathrm{\rightrightarrows}}{}}{\gamma}\]
  • Shear strain rate tensor:

\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{\gamma}= 2 \left( \overset{\underset{\mathrm{\rightrightarrows}}{}}{e} - {1 \over 3} (\nabla \cdot \vec{u}) \overset{\underset{\mathrm{\rightrightarrows}}{}}{I} \right)\]
  • Shear strain rate tensor:

\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{e}= {1 \over 2} \left( \nabla \otimes \vec{u} + (\nabla \otimes \vec{u})^T \right)\]
  • Hence:

\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{\sigma}=-p \overset{\underset{\mathrm{\rightrightarrows}}{}}{I} + \mu \left( \nabla \otimes \vec{u} + (\nabla \otimes \vec{u})^T - {2 \over 3} (\nabla \cdot \vec{u}) \overset{\underset{\mathrm{\rightrightarrows}}{}}{I} \right)\]

4.1.12.7. What is the shear strain rate tensor?¶

  • In Einstein notation:

\[e_{ij} = {1 \over 2} \left( {{\partial u_j} \over {\partial x_i}} + {{\partial u_i} \over {\partial x_j}} \right)\]
\[\begin{split}e_{ij} = \begin{bmatrix} {{\partial u_1} \over {\partial x_1}} & {1 \over 2} \left( {{\partial u_2} \over {\partial x_1}} + {{\partial u_1} \over {\partial x_2}} \right) & {1 \over 2} \left( {{\partial u_3} \over {\partial x_1}} + {{\partial u_1} \over {\partial x_3}} \right) \\ {1 \over 2} \left( {{\partial u_1} \over {\partial x_2}} + {{\partial u_2} \over {\partial x_1}} \right) & {{\partial u_2} \over {\partial x_2}} & {1 \over 2} \left( {{\partial u_3} \over {\partial x_2}} + {{\partial u_2} \over {\partial x_3}} \right) \\ {1 \over 2} \left( {{\partial u_1} \over {\partial x_3}} + {{\partial u_3} \over {\partial x_1}} \right) & {1 \over 2} \left( {{\partial u_2} \over {\partial x_3}} + {{\partial u_3} \over {\partial x_2}} \right) & {{\partial u_3} \over {\partial x_3}} \end{bmatrix}\end{split}\]
  • In vector notation:

\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{e}= {1 \over 2} \left( \nabla \otimes \vec{u} + (\nabla \otimes \vec{u})^T \right)\]

4.1.12.8. How is the compressible Navier-Stokes momentum equation derived from the Cauchy equation using the shear strain rate tensor?¶

  • Cauchy:

\[{D \over {Dt}} (\rho \vec{u}) = \nabla \cdot \overset{\underset{\mathrm{\rightrightarrows}}{}}{\sigma} + \rho \vec{g}\]
  • Total stress tensor:

\[\overset{\underset{\mathrm{\rightrightarrows}}{}}{\sigma} = -p \overset{\underset{\mathrm{\rightrightarrows}}{}}{I} + \mu \left( \nabla \otimes \vec{u} + (\nabla \otimes \vec{u})^T - {2 \over 3} (\nabla \cdot \vec{u}) \overset{\underset{\mathrm{\rightrightarrows}}{}}{I} \right)\]
  • Taking the divergence of each part:

\[\nabla \cdot \overset{\underset{\mathrm{\rightrightarrows}}{}}{\sigma} = \nabla \cdot (-p \overset{\underset{\mathrm{\rightrightarrows}}{}}{I}) + \mu \nabla \cdot \left( \nabla \otimes \vec{u} + (\nabla \otimes \vec{u})^T \right) - {2 \over 3} \mu \nabla \cdot ( (\nabla \cdot \vec{u}) \overset{\underset{\mathrm{\rightrightarrows}}{}}{I} )\]
  • First part:

\[\nabla \cdot (-p \overset{\underset{\mathrm{\rightrightarrows}}{}}{I}) = -(\nabla \cdot \overset{\underset{\mathrm{\rightrightarrows}}{}}{I})p - (\overset{\underset{\mathrm{\rightrightarrows}}{}}{I} \cdot \nabla)p = -\nabla p\]
  • Second part:

\[\mu \nabla \cdot \left( \nabla \otimes \vec{u} + (\nabla \otimes \vec{u})^T \right) = \mu \left(\nabla^2 \vec{u} + \nabla (\nabla \cdot \vec{u}) \right) = \mu \nabla^2 \vec{u} + \mu \nabla (\nabla \cdot \vec{u})\]
  • Third part:

\[-{2 \over 3} \mu \nabla \cdot ( (\nabla \cdot \vec{u}) \overset{\underset{\mathrm{\rightrightarrows}}{}}{I} ) = -{2 \over 3} \mu \left( (\nabla \cdot \overset{\underset{\mathrm{\rightrightarrows}}{}}{I}) \nabla \cdot \vec{u} + (\overset{\underset{\mathrm{\rightrightarrows}}{}}{I} \cdot \nabla) \nabla \cdot \vec{u} \right) = -{2 \over 3} \mu \nabla (\nabla \cdot \vec{u})\]

where: \(\nabla \cdot \overset{\underset{\mathrm{\rightrightarrows}}{}}{I} = 0\) and \(\overset{\underset{\mathrm{\rightrightarrows}}{}}{I} \cdot \nabla=\nabla\)

  • Adding first, second and third parts (plus \(\rho \vec{g}\)):

\[{D \over {Dt}} (\rho \vec{u}) = -\nabla p + \mu \nabla^2 \vec{u} + \mu \nabla (\nabla \cdot \vec{u}) -{2 \over 3} \mu \nabla (\nabla \cdot \vec{u}) + \rho \vec{g}\]
  • Simplfiying:

\[{D \over {Dt}} (\rho \vec{u}) = -\nabla p + \mu \left( \nabla^2 \vec{u} + {1 \over 3} \nabla (\nabla \cdot \vec{u}) \right) + \rho \vec{g}\]

4.1.12.9. What are the meaning of the terms in the fully compressible Navier-Stokes equations?¶

\[{\partial \over {\partial t}} (\rho \vec{u}) + \nabla \cdot (\rho \vec{u} \otimes \vec{u} ) = -\nabla p + \mu \left( \nabla^2 \vec{u} + {1 \over 3} \nabla (\nabla \cdot \vec{u}) \right) + \rho \vec{g}\]
  • Unsteady momentum:

\[{\partial \over {\partial t}} (\rho \vec{u})\]
  • Advective momentum:

\[\nabla \cdot (\rho \vec{u} \otimes \vec{u} )\]
  • Pressure gradient:

\[- \nabla p\]
  • Viscous or diffusive term:

\[\mu \nabla^2 \vec{u}\]
  • Compressibility:

\[{1 \over 3} \mu \nabla (\nabla \cdot \vec{u})\]
  • Body forces:

\[\rho \vec{g}\]

4.1.12.10. Expand the terms in the Navier-Stokes equations assuming \(\nabla \cdot \vec{u} = 0\)¶

  • Navier-Stokes:

\[{D \over {Dt}} (\rho \vec{u}) = {\partial \over {\partial t}} (\rho \vec{u}) + \nabla \cdot (\rho \vec{u} \otimes \vec{u} ) = -\nabla p + \mu \left( \nabla^2 \vec{u} + {1 \over 3} \nabla (\nabla \cdot \vec{u}) \right) + \rho \vec{g}\]
  • \(x\)-direction as principal:

\[{\partial \over {\partial t}} (\rho u) + {\partial \over {\partial x}} (\rho u^2) + {\partial \over {\partial x}} (\rho uv) + {\partial \over {\partial x}} (\rho uw) = -{{\partial p} \over {\partial x}} + \mu \left( {{\partial^2 u} \over {\partial x^2}} + {{\partial^2 u} \over {\partial y^2}} + {{\partial^2 u} \over {\partial z^2}} \right) + \rho g_x\]
  • \(y\)-direction as principal:

\[{\partial \over {\partial t}} (\rho v) + {\partial \over {\partial x}} (\rho vu) + {\partial \over {\partial x}} (\rho v^2) + {\partial \over {\partial x}} (\rho vw) = -{{\partial p} \over {\partial y}} + \mu \left( {{\partial^2 v} \over {\partial x^2}} + {{\partial^2 v} \over {\partial y^2}} + {{\partial^2 v} \over {\partial z^2}} \right) + \rho g_y\]
  • \(z\)-direction as principal:

\[{\partial \over {\partial t}} (\rho w) + {\partial \over {\partial x}} (\rho wu) + {\partial \over {\partial x}} (\rho wv) + {\partial \over {\partial x}} (\rho x^2) = -{{\partial p} \over {\partial z}} + \mu \left( {{\partial^2 w} \over {\partial x^2}} + {{\partial^2 w} \over {\partial y^2}} + {{\partial^2 w} \over {\partial z^2}} \right) + \rho g_z\]

4.1.12.11. How is the compressibility term expanded in the Navier-Stokes equations?¶

  • Compressibility term:

\[{1 \over 3} \nabla (\nabla \cdot \vec{u})\]
  • \(x\)-direction as principal:

\[{1 \over 3} {\partial \over {\partial x}} \left( {{\partial u} \over {\partial x}} + {{\partial v} \over {\partial y}} + {{\partial w} \over {\partial z}} \right)\]
  • \(y\)-direction as principal:

\[{1 \over 3} {\partial \over {\partial y}} \left( {{\partial u} \over {\partial x}} + {{\partial v} \over {\partial y}} + {{\partial w} \over {\partial z}} \right)\]
  • \(z\)-direction as principal:

\[{1 \over 3} {\partial \over {\partial z}} \left( {{\partial u} \over {\partial x}} + {{\partial v} \over {\partial y}} + {{\partial w} \over {\partial z}} \right)\]

4.1.12.12. What is the skew symmetric form of the total derivative?¶

\[{D \over {Dt}} (\rho \vec{u}) = {{\partial \vec{u}} \over {\partial t}} + {1 \over 2} \left( (\vec{u} \cdot \nabla) \vec{u} + \nabla \cdot (\vec{u} \otimes \vec{u}) \right)\]

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